So what you would like to do today is we would finalize a little bit our discussion of linear
parabolic equations where we have now seen existence, a proof of existence for weak solutions
and quite weak assumptions in particular also for the right hand side only requiring that
then of course L2 in time but only H minus 1 in space function allowing for concentrated
sources. So as you know already one important property of elliptic and parabolic equation is
the maximum principle. The maximum principle comes in various versions very weak formulations up to
very strong formulation the most strong formulation which holds also true in the parabolic sense but
only for classical solutions is that if a maximum is attained in the aetheria the solution is
necessarily constant, constant up to this point so to speak in the parabolic cylinder up to this
time level and then there are all that would be the strong maximum principle then there are
weaker forms only saying the maximum is attained at the boundary and as a consequence there are
comparison principles which ensure uniqueness and most weak formulation which also holds true for
this general solutions which we have is the following. So we are looking at a solution in
the most weak sense so L2 in time H1 in space should be a solution of let's say our standard
equation but that is not so important so this minus Laplace of U can also substitute it by a
general elliptic operator the only thing one has to deal with take care of is the zero order term
which appears in it so there the corresponding signs have to hold but for example first order
terms convective terms there's no restriction whatsoever but we formulate it here in this form
first of all for the homogeneous case I will say something for the inhomogeneous case in a second
and okay then we have initial data and we have boundary data which are here supposed to be
Dirichlet boundary data that's strange okay delta omega t okay so the assumptions the regularity
assumptions are supposed to be okay U0 being an L2 function this was the most general situation
which we had the G is supposed to be an L2 function so the G to be understood as the
prolongation is this necessarily existing prolongation of the boundary data because
the G has to be a trace in space so in the prolongation it should be an H1 function that's
the one thing and we have seen what we further at least need to do the way we did to prove namely
so to speak subtracting the G from the problem we also need something on the time derivative of the
G so we need something on H1 in L in time but here we only need very weak things namely to be a dual
element and being an H minus one of omega so that's the standard assumption and this very weak
formulation of the of the maximum principle is the following if there is a bound for the initial
data of course that means it's actually an L infinity does not mean it's an infinity function
because it's only a one-sided statement here but it goes in the direction the same thing for the
Dirichlet data so we had then the consequence is that the whole solution U is also less or equal
to this constant on Qt so that would be a result which follows from all the other versions of the
maximum principle I have stated so in this sense is a very weak formulation but it already requires
weak assumptions so what kind of so first of all the same thing of course could be also stated as
a minimum principle because then we just look at minus U as this is possible because we have
here a homogeneous equation if you would have an inhomogeneous equation the question is how in which
way the sign of the right hand side and the sign of the source comes in and the proof basically the
proof is cut just comes by at least formally the proof is very simple to make it rigorous is not
not that simple the formal proof is we just test so we just test with a specific function namely
with a test function U minus M plus what we would like to see is that U is less or equal to M that
is we would like to see that the plus part of this function is zero we'd like to prove that this
phi is zero that is to show is phi is equal to zero and if we do the question now is a little
bit how to do derivatives with this how to compute derivatives of this function here because as you
will imagine there is so to speak the set U equals to M and at the set U equals to M typically this
function will be continuous but not differentiable so we can only deal with weak derivatives and we
have to know how to compute the weak derivatives of this function and how to compute the weak
derivatives this is said this is that there is something which is called Stumpakia's lemma
to see Stumpakia's lemma that tells us that tells us that if we would like and that is for the
Presenters
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Dauer
01:18:25 Min
Aufnahmedatum
2018-05-03
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2018-05-03 15:57:08
Sprache
de-DE